ʸ
դxȤơ

ѷBCPž
ջѷĤꡢƱʻѷߤĤΩƤ

ɬפϤʤ = 5-1 = 4
5*4/2 = 10

˲㤬뤫⤷ʤ
82ڡ 0:10:54 39643
ʸ
ʤߤ
x^2 -5x - 4 = 0
x = (5 + sqrt(41))/2
Ǥ֤
82ڡ 0:12:47 39644
xxx
̲ΤǤͤޤģڣ
82ڡ 0:13:10 39645

http://www.dotup.org/uploda/www.dotup.org3264750.jpg
ʤ󤸤

ʬ餤׻褦¤äƤޤ
82ڡ 0:14:45 39646

ģäαĹˣãѡǡѤȤʤѡǤȤС
ѣУ£ѡǡᣴ٤դ
£ѣйƱ£ѡǣФȤʤꡢ
ѡܣãСУѤ롣

ޤѣʿԣУ¤ꡢ
ңãУ

ΣդȤȡ

ҡݣ
ѡʣ
ѣġ᡼ʣܣ
ģС
Уѡʣܣ

ѷУģѤ˻ʿѤƼС
ʣᣴ
ѡᣴ
82ڡ 0:25:56 39647
ͣ.ǥ
£ãФ¤濴Ȥȿײ90žΤ򻰳ѣ£С
ȤȤѣҤαĹȣСǣ¤θȤȤޤ
£ѣȤľջѷȤʤꡢ£ȡѣȡ....ʢ
ѣСǣȢᢤ£ңȡ
衡ѣСǡ£ҡ5ѣ514
äơѡ1/2*5*410ȵޤ

̸嵭͡ʢˤʬץߥ򤷤ƤΤǡޤ
84ڡ 0:58:14 39648

AR=t ȤơARQ梤CPBꡢAQ=t^2+5tBQR=5(t^2+5t)/2
ϫޤɺɸ򤪤
BPμȡBQμηˣľΤʤѤ45٤
tanβˡȤäơꥴμǵޤ
t^2+5t-4=0 ꡢt^2+5t=4 äơѤϡ10
ݤʲ򤷤ΤϻΤϤorz
裲롼ס 82ڡ 1:43:15 HomePage:39649
ϥ饮㡼ƥ
Ϥ褦ޤˤMATHEMATICA׻Ǥβ򤬽ФƤ
դ֤Τ˶ϫޤ
82ڡ 9:00:44 HomePage:湩ؤإ39650
uchinyan
Ϥˤϡơϡ
ϡȤƤϲ󤫸ѥʤΤǴñǤ礦ʴǡ

BCP B 濴ȿײ 90ž BC BA ˽Ť P ΰư P' ȤQR Ĺ BP' Ȥθ S Ȥޤ
ABCD ʤΤǡBC = BA C ΰư A ˤʤꡤ
SBQ = P'BQ = P'BA + ABQ = PBC + ABQ = ABC - QBP = 90- 45= 45= SQBǤ
ǡSBQ ľջѷʤΤǡSB = SQBSQ = 90= P'SQǤ
ǡP'QS RBS ͤȡSQ = SBP'SQ = 90= BSQ = RSB
ˡPBQ = 45= RQB BP//RQ AD//BC Ǥ⤢Τ P'QS = PBC = P'BA = RBS Ȥʤäơ
P'QS RBSQP' = BRAQ = QP' - AP' = BR - CP = 5 - 1 = 4 cmǤ
ꡤBQR = BR * AQ * 1/2 = 5 * 4 * 1/2 = 10 cm^2ˤʤޤ
ͥνȡ 82ڡ 11:09:07 MAIL:uchi@sco.bekkoame.ne.jp 39651
uchinyan
ǼĤɤߤޤ
ϴñȻפäΤǤʳ˶ϫʤäƤ¿褦Ǥ

#39646#39648#39651
BCP B 濴ȿײ 90ž BC BA ˽Ť P ΰư P' ȤQR Ĺ BP' Ȥθ S Ȥȡ
SBQ ľջѷP'QS RBS Ʊˤʤ뤳ȤȤˡ

#39643Ⱦ#39644#39647#39649#39650
ؤˤˡ׻̤ʤɤˤϤʤ꺹褦Ǥ
ʤ#39643θȾ#39646ʤɤΤ褦˸ʤʤΤǤܺ٤ʬ餺Ⱦδϻɤϡ֡פǤ
ͥνȡ 82ڡ 11:38:17 39652

Ǥ
ǶᡢǤˤ⤹뤳Ȥ¿ơ
ĴǤ
82ڡ 13:25:19 39653
namba
ͤɸǤ

B(0,0),C(a,0)ȤP(a,1),Q(a^25a,a)
QBP=45Ǥꡢ٥ȥQB,PBѤͤ롣
a˴ؤ4򤯤ȡa=2,3,a^25a4=0
a>5ǤΤǡa^25a=4ȤʤQC=4
äƢQBPѤ10cm^2Ȥʤޤ
82ڡ 14:44:23 39654

QS=SBȤʤSľQR˼ꡢAR=aȤ롣ͳѷABCDǤ뤳Ȥ顢ѷ3ʿȤäRQRSSB롣RQ+RS=SBꡢ3a^3+10a^2+26a+5=0ʤ(a+5)(a^2+5a-4)=0Τǡa>0ꡢa^2+5a=4AQĹΤǡäơѤ5*4/2=103ϵǤorz
83ʶ 1:16:59 39655

ʬ3ְäƤޤorza^3+10a^2+21a-20=0Ǥ
ϵ塡 83ʶ 1:42:47 39656

#39648 ޤDz򤯤Τ1ޤǤȾʬǤ
83ʶ 3:34:29 HomePage:39657
ʸ
#39652
> ʤ#39643θȾ#39646ʤɤΤ褦˸ʤʤΤǤ
̤ꡢˡϤޤäǤ
դx֤ɻȤɬפʤäȤǤ

Ĥ狼ˤƤߤޤ󡰡
83ʶ 14:44:19 39658
HirotakaUEDA
ʬx-yɸΥդȤˡDz򤤤ƤߤޤäƥäΤǤʤȤǤ
ľBQy=(t+1)/(t-1)x ľRQy=(1/t)x+5 Ĥθyɸ᤽줬tȤ
t^2-5t-4=0롣AQĹt^2-5tǤĤޤ4cmȤ狼ΤǡѷBQRѤ10cm^2

¾γΥ쥬Ȥʲˡ򸫤ƤȼʬꥴϵȤȤʬäѤǤ
83ʶ 16:23:00 39659
HirotakaUEDA
#39648βCH=BHȤȤϡή줫餤BH=QHʤΤǤϤʤȻפޤ
ǰΤ
83ʶ 16:37:49 39660
HirotakaUEDA
˺Ƥޤ#39659ˤtΰդĹǤʤߤt=(1/2)*(5+41ˤǤ
83ʶ 17:16:40 39661
⡼ޥ
ʤۤ!!
̵ǽФ...Σ=(5+41)/2...AQ=4
޷Ūˡ䤫ޤޤȻפΤ餵ޤ...^^;
...BQRBDPɤȤФä...׹ߤ㤤ޤ...^^;;...
83ʶ 18:21:02 39662
mukku
׻ǵͤΤǡȻǤޤ
ڤäǤ
83ʶ 23:21:16 39663
ͣ.ǥ
HirotakaUEDA#39660Ǥ Ŧͭ񤦤ޤ
ĤȤǡѤȣä򸫴ְ㤨ƥץߥ򤷤Ƥޤ
®Ƥ餤ޤ
84ڡ 0:53:41 39664

ģαĹˣ=1cmȤʤӤꡢ
ѣҤαĹȣ£ӤθԤȤ
£Ӣᢤã£С顡ܣԣ£=١ˤʤΤǡԣ=ԣ
줫顢ѣӣԢᢤ£ңԡΤǡӣ=5cm
äơ=4cm ˤʤ뤫顢Ѥϡ542=10cm2
84ڡ 17:03:29 39665
Ȥ
ɸ֤ޤ

ɸB(0,0),C(a,0),P(a,1),D(a,a),A(0,a)֤tan(PBC)=1/a
ľBQ:y=tan(PBC+45*%pi)*x
y=(1+tan(PBC))*x/(1-tan(PBC))
y=(1+1/a)*x/(1-1/a)
factor((1+1/a)/(1-1/a));(a+1)/(a-1)
y=(a+1)*x/(a-1) Qy=a Ȥ
Q(a*(a-1)/(a+1),a)
ǢQRBȹƱʢBSQ
SQľBP:y=x/aˤȤθ
S(a*(a-1)/(a+1),(a-1)/(a+1))
RB=5=SQ=a-(a-1)/(a+1)
solve(a-(a-1)/(a+1)=5,a);a=(5-sqrt(41))/2(ŬĹޥʥ),a=(sqrt(41)+5)/2
ǢRQBRQ*Qxɸ/2ǵ
a:(sqrt(41)+5)/2$
expand(factor(expand(5*a*(a-1)/(2*(a+1)))));10()
˭ԡ 86ʷ 2:43:06 MAIL:fttnm528@ybb.ne.jp 39666

RPBQθSȤȡRSQ,SBPľջѷBS^2+RS^225BC=ȤȡRS^2RQ^2(a-5)^2{a(a-5)}^22BS~2=BP^2a^2+1μa^4-10a^3+27a^2-10a-24=0BQR5a(a-5)/2a(a-5)Ȥ4x^2+2x-24=0ȤʤΤx=4줫颤BRQ=10ˤɤ夭ޤɤ줤ʤФΤϥۥäȤΤǤߤʤβٶƤ餤ޤ
86ʷ 11:47:42 39667

幻ͥ饹
88ʿ 21:44:02 39668