Фϡ֤ꤿޤ޲򤱤ޤ
ADR, BCSȤ
RN=SM=12, RM=SN=9, MN=15
ͳѷRNSMĹޤ
PR=SQ=PS=RQ=25/2ʤΤ
PSRջѷ
RSXȤRXRSϿľ
PXRˤ3:4:5λѷ
PX=10, PQ=20Ȥʤޤ
򤫤äǤ᤯ʤСm(__)m
114ڡ 0:39:19 44037
⡼ޥ
椪񤤿夲ޤ
䤳äɡ^^;
Jޥޤ..PRQSȤ狼ΤǡPQľRS...錄Τøˡ줿Τ ^^;...
25^2-12^2-9^2=400=PQ^2
PQ=20
ʤϤáOrz...
¨ ^^;v 114ڡ 1:19:09 44039
Ȥ
ɸB(-25/2,0,0),D(25/2,0,0),BC=aȤߤθȤCx,yɸ(z=0)
AD=bȤ3ߤθȤAMN=15PQͤޤ롡XMaxima

solve([(x-25/2)^2+y^2=24^2,(x+25/2)^2+y^2=a^2],[x,y])$
part(%,1)$rhs(part(%o2,1))$rhs(part(%o2,2))$
solve([(x-25/2)^2+y^2+z^2=b^2,(x+25/2)^2+y^2+z^2=18^2,(x-%o3)^2+(y-%o4)^2+z^2=25^2],[x,y,z])$
part(%,2)$rhs(part(%o6,1))$rhs(part(%o6,2))$sqrt(factor(rhs(part(%o6,3))^2))$
factor((%o7+%o3)^2/4+(%o8+%o4)^2/4+%o9^2/4-15^2)$
factor((%o7-25/2-25/2-%o3)^2/4+(%o8-%o4)^2/4+%o9^2/4)$
sqrt(expand(%-%th(2)));20()
˭ԡ 114ڡ 2:00:00 MAIL:fttnm528@ybb.ne.jp 44040
٥륯åĥ
äȲ򤱤ޤ
񤤤ƤѤʤΤ
ġ£äء٤Ȥޤ
أͣ٣ΤʿԻշdzդĹ912гͣΤ15ʤΤ345Ĺ١ͣΡ15
ҤУͣѣΤϰդ12.5ͣΤ15ʤΤǡг4ʬ345ľѻѷǤΤǡУѡ20ʬޤ
УͣѣΤҤʤΤϣ£áĤʤɤǧУͣѣΤʿˤƾ夫鸫dzΤޤ
114ڡ 2:48:18 44041
ma-mu-ta
λѿA-BCDϡ
ABãĤޤऽ줾̤ г18241դ15ɩ Ȥȡ
̤Ȥ ⤵20 λͳळȤǤޤ
ȡУѡ⤵20Ȥʤޤ
ޤϤ https://db.tt/x771IOB8

гξͤޤΤǡ#44057

115ʶ 18:24:15 44042
̴
ma-mu-taͤο޺ǹǤ͡ˤ䤬ڤޤ
ɤ餳ͤΩΤȯۤפ⤫֤ΤǤΩδФ
̵ˡ
ٻΤ桡 114ڡ 7:38:30 44043

椪񤤿夲ޤ
ǤϽɹܳŪߤäƤޤޤ
ͤˤϺǯꤤޤ
ޤ轵ޥ뤵ˤϡϤɤʤɤ;פʥץå㡼򤪳ݤƤޤäȿʡƱ˺ä񤷤ˤʤΤǤϤȶݡˤǤ
ѤʴФΤǡУΣѣͤʿԻշˤʤ뤳Ȥʤޤг狼äƤȤ⤦г顢Ҥ餤Ĺ򻻿ǵ뤳ȤϤǤʤϤ顢ϤʤʤȤʤȤˤɤ夭ޤ(δϤƤ褦ǤǤ
1ǯ֤ˤ϶ʱˤɬפȼʬ֤ĤġߤʤβǺǯٶƤޤ

Ϻꡡ 114ڡ 7:42:40 44044
ǯ
BCRADSȤȡ
MRNSϡ129г15cmˤĹʤΤǡRSMN15cm
PRQSϰ25/2cmΤҤΤPQ10220cmޤ
ƸгƱǤ
ܥ⤢ޤ빽ɤǤǯ

114ڡ 12:25:20 44045
Ȼ
ǯ⵹ͤޤ
114ڡ 12:25:08 44046
uchinyan
Ϥˤϡơϡ
ǯܤ϶ֿ޷Ǥ̤͡ˤϤ񤫤ʤȻפΤλǤɸŪʤȻפäΤǤ
ΨϢν­򸫤ȤפʤΤΤޤ͡Ϥ껻Υ٥Ϲ⤤Ǥ
򸫤ȥ٥ȥDz򤭤ʤޤǤǤϤȹͤޤ
ĤΤϢȤƤαѡȿͤ 345 ʡȤ櫓ǡʴ

ޤ̤ˡABC ˤơMN 줾 ABAC ĤޤꡤAM = MBAN = NCΤȤ
AMMB = 11 = ANNCAMAB = 12 = ANACAMN ABC 12MN//BCMN = BC/2
ޤʲǤϤΤȤȤޤ
ޤդ椬 345 ΤȤľѻѷȤȤȤޤ

ADBC Τ줾 EF Ȥޤ
DAB ˤơDE = EADM = MBꡤEM//ABEM = AB/2 = 18/2 = 9 cm
CAB ˤơCN = NACF = FBꡤNF//ABNF = AB/2 = 18/2 = 9 cm
ACD ˤơAN = NCAE = EDꡤNE//CDNE = CD/2 = 24/2 = 12 cm
BCD ˤơBF = FCBM = MDꡤFM//CDFM = CD/2 = 24/2 = 12 cm
ǡEMFN MN EF гȤʿԻշǡ
NFM ͤȡNFFMMN = 91215 = 345ǡNFM = 90ľѻѷǤ
ꡤEMFN ĹˤʤꡤĤгĹΤǡEF = MN = 15 cmǤ
ˡƱͤˤơEPFQ ͤޤ
ABD ˤơAP = PBAE = EDꡤPE//BDPE = BD/2 = 25/2 cm
CBD ˤơCF = FBCQ = QDꡤFQ//BDFQ = BD/2 = 25/2 cm
BAC ˤơBP = PABF = FCꡤPF//ACPF = AC/2 = 25/2 cm
DAC ˤơDE = EADQ = QCꡤEQ//ACEQ = AC/2 = 25/2 cm
ǡEPFQ EF PQ гȤʿԻշǤPE = 25/2 = PF ¤ϤҤǤ
ꡤEF PQ θ O ȤСEOP EOP = 90ľѻѷǡ
EO = EF/2 = 15/2 cmEOPE = (15/2)(25/2) = 35EOP 345 ľѻѷǤ
ǡPQ = PO * 2 = PE * 4/5 * 2 = 25/2 = 4/5 * 2 = 20 cmˤʤޤ
ͥνȡ 114ڡ 13:07:37 44047
uchinyan
ǼĤɤߤޤ


ʲεҤϡ⤽ϻ伫ȤٶΥ˲᤮ʤΤǤ
޳ѤʤΤǤͤޤǤˤȻפäƸΤǤ
Ȥ⤢äơˡʬϻ F.A.Q. ΡֻϰϡפεҤ򻲹ͤˡ
ĿͤǤиǼŪ˹ԤäƤΤǤäơҴŪʤΤǤϤޤ
ޤǤ⤴ͤǤ餺

ࡤν񤭹ߤ򸫤Ƥȡʤ˶ϫ줿¿褦ʤΤǡ
٤ϡɸŪ񡤤ΤʡȤ⤷Ƥޤ

ˡȤƤϡȤˡAD RBC SȤơ
RNSM ĹRPSQ ҤѤˡΤ褦Ǥ͡
ΤȤʬäƤޤСͳؤߤ񤷤ʤǤ礦
äȤ⡤λͳѤľܤϢۤΤϤñǤϤʤǤ
ľΤڤФʤɤηи˭٤ʤгΤ˻פդƤ⤤ʤ
Ȥפޤ
ͥνȡ 114ڡ 13:45:25 MAIL:uchi@sco.bekkoame.ne.jp 44048
ȤޤԤ
ѥåץȤäơŪȤޤ
MNʤɤĹϡդĹǴñɽǤޤ
114ڡ 14:08:53 44049
ޤ
ѷУ£Ѥľѻѷˤʤ뤳ȤѤƲ򤭤ޤɤǤ礦
£ѤĹΣϣݣᣴ
У¡᣹УѤΣϣݣߣᣴ
Уѡᣲ
äƤΤʡιͤϡ

114ڡ 14:41:25 44050
uchinyan
ʤߤˡ٥ȥȤäˡ
ͤȤ׻Dz򤱤ޤ͡

٥ȥAB = a٥ȥAC = b٥ȥAD = cȤȡ
AB = |a| = 18AC = |b| = 25
BD = |a - c| = 25BD^2 = |a|^2 - 2(ac) + |c|^2
CD = |b - c| = 24CD^2 = |b|^2 - 2(bc) + |c|^2
MN = |(a + c)/2 - b/2| = 15MN^2 = |a - b|^2/4 + 2((a - b)c)/4 + |c|^2/4
PQ^2 = |a/2 - (b + c)/2|^2
= |a - b|^2/4 - 2((a - b)c)/4 + |c|^2/4
= MN^2 - (a - b)c
= MN^2 + (BD^2 - CD^2 - AB^2 + AC^2)/2
= 15^2 + (25^2 - 24^2 - 18^2 + 25^2)/2
= 225 + (625 - 576 - 324 + 625)/2
= 225 + 175
= 400
PQ = 20 cm
ͥνȡ 114ڡ 14:57:41 MAIL:uchi@sco.bekkoame.ne.jp 44051

֤ȣᣳľѻѷˤʤΤ
٤УȣĹˤʤä
PQϻͳѿι⤵Σܤǡ⤵ϣ/ȣ/ȡǡ
ľѤˤʤΤϣξǡϣ/
PQܤʤΤǣ
Ȥޤʤ󤫤øǡޤڤޤ(-_-;)
114ڡ 16:26:39 MAIL:nikotan@fat.coara.or.jp 44052

ǯꤤޤ
115ʶ 11:34:48 HomePage:44053
uchinyan
#44050
仰ѷУ£Ѥľѻѷˤʤ뤳ȤѤƲ򤭤ޤɤǤ礦

äƤΤʡιͤϡ
ࡤǤ礦äƤ뤫Ȥȡäȡ

¤Ϥϼͳ٤ĻĤäƤޤ
PQAB ȤȡAD = AC = BC = BD = 25 ȤʤüˤʤäƤȻפޤ
ˡǤͿ줿狼 PQAB ȤϸڤʤΤǤϤʤΤǤ礦

ΰ̣Ǥϡ#44042οޤäȵˤʤäƤޤ
ͥνȡ 115ʶ 13:15:25 44054
Τ
ס˥󥸤ޤ
ʤफҲʲˤäƥڡ򤷤Ƥޤ֤Ǥ

ޤ޿ǯȯܤä褦ʤΤǡ轵󥸤Ƥȵ򿷤ˤޤ
ߤʤޤꤤޤ

ADBC򤽤줾SRȤ롣
ͳѷNRMSϡNRSM9NSRS12гNMRSĹȤ15Ĺ
ͳѷPRQSϡդĹ12.5ΤҤгңӤĹ15
ǡΤҤгθOȤȡ
ѷOPRϼդĹ12.5¾ΰդĹ7.5ľѻѷ
äơ345ľѻѷȤʤΤǡOP10
äơPQ20
115ʶ 15:43:18 44055
ma-mu-ta
#44054uchinyanζĤ̤Ǥ
ľξϡADACBCBD25 Ȥʤޤ
гξϡADBC 25 ȤϤʤޤ
#44042ä˸ڤʤäΤǤ
ޤϽ褬äΤUPʤäΤǤ
https://db.tt/CUVsHqp4
AFBEGDHC1դ15ɩABGH18EFCD242Ĥ̤ʿǤȻפäƤ
AECGFBHDϽ2015ĹAGDFECHBդ2015ʿԻշ Ǥ
ξ MN15PQ20 Ȥʤޤ
115ʶ 18:12:21 44057
ǯ
#44050, #44054
#44054 η׻ߤ BC=AD=AB=CDʤξǭPBQľѻѷˤʤˤˤü첽Τ褦Ǥ
MN=15cmѤƤ餺ü첽ξMN=15Ƥ뤳ȤǧɬפꤽǤ
PBQ=ȤȡMN^2=(9cos)^2+(9sin)^2+12^2=225MN=15ȤʤΤǡü첽ˤȤʤäƤ롣
λѿηϡAC=BD=25cmξβBCD̤ؤƿޤABCDʻѿǤ90٤ΤͤˤǤФ褤ȹͤ롣ʤƤPQABˤʤ뤫ɤ̤Ƥ

115ʶ 21:04:22 44058
ˤ⡼
ää
ͣΤĹȡͣΤȣУѤ˲ȤʤľѻѷƤơ㤢УѤϣʤȻפä衣
115ʶ 22:17:04 44059

УΣͣѤܤƤ黰ʿȤޤԥߥå˵դΤ˻֤ޤ
116ڡ 9:26:56 44060
uchinyan
#44057ma-mu-ta
ȿޤɲä򤢤꤬Ȥޤ
ʿޤ⤢ʡȻפäƤޤ
#44042ǤñˡֻͳפȤΤǡΤ褦ʤΤޤࡤ򤷤ƥȤޤǤ
#44050ǡPQAB פȡޤˤʤꡤȤǤ

#44058ǯԤ
ͻ򤢤꤬Ȥޤ
ϡMN = 15 ʳξΤȤǡ
MN = 15ȡABCDƱͤǡͳ٤ĻĤꡤ
MN = 15 PQABȡAD = BC = 25Ʊͤǡͳ٤ϻĤޤ
ΤȤͤˤʤСȻפޤ
ͥνȡ 116ڡ 13:58:22 44061
Ȼ
ͳ٤Τʿ̤ǹͤޤACBŤʤäPQ20ϽФޤPQͳǤƤޤ
116ڡ 20:54:41 44062
Ϸʼ
ޤ򤷤Ƥ¤ȣäŤʤꡢ飲줿ä㤤ޤ
β򻲹ͤˤƼΤ褦ʶڤͤޤ
ĤӤȤޤ
ӣΤϣģäȾʬǣǤ
ӣͤϣ¤ȾʬǣǤ
ӣͣΤϢܣͣӣΤ٤ΣѷǤʣդ
ӣΤȣģáӣͤȣ¤ʿԤǤ
ģäȣ¤ϿľǤ
ӣΤǣãѤƱʤΤǣ¤ȣäŤʤޤ
УäѣäʤΤǡУѤϣȲ򤭤ޤ
ʡ 118ʷ 9:18:31 44063