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ãͤȣ£ѤαĹҤ֤УãҤϣľѻѷǤ͡

ƥӤ򸫤ˣ礦ɤꤹΤϵפ֤ǤƤ
˻Ϥ褦Ⱦޤ̵ʤΤǤ
115ڡ 1:41:44 35298
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ʿԻշޤ
115ڡ 0:11:55 MAIL:eityans@gmail.com HomePage:֥35299

APBQθRȤ롣
APCQ,CPBQϤȤʿԤʤΤǡͳѷPCQRʿԻշǤ롣
äơMPQ2ʬƤΤǡC,M,R1ľˤ롣
CR=4ѤʬΤǡ
PRQ=3*4*1/2=6ʭѡ2)
PABQ:PRQ=(1-5/8*3/8):5/8*3/8=49:15
PABQ=6*49/15=98/5(ѡ2)
115ڡ 0:19:50 35300
mhayashi
ͳѷУ£ѡʻͳѷУã͡ˡܡʻͳѷͣã£ѡ
ʤΤǡͣФͣѤȽŤʤ褦ˡͤ濴˻ͳѷУãͤžޤ
KANSAI 115ڡ 0:32:23 HomePage:M.Hayashi's Web Site35301
ޥ
դߥϤʤä褦DzǤȤꤢܴۤʥꥸʥäΤǡä԰¤Ǥ
PowerBook 115ڡ 0:36:09 MAIL:masaru-y@sansu.org HomePage:Men @ Work35302
⡼ޥ
Ʊ褦ʤΤǤ...^^;
APBQĹƤθRȤ礭ջѷRABǤ롣
ȡRPCQʿԻշǡѷRCPѷBRC4:3:5ľѻѷ
ͳѷPABQ=4*8*(1/2)+(4*8-3*4)*(1/2)*(3/5)^2=16+18/5=98/5
115ڡ 0:53:46 35303
baka
餷ꥸʥꤢ꤬Ȥޤ
ˤ褦䤯򤱤ޤ
ϼ͡ϼ͡
115ڡ 1:37:14 35304
(Keigei)
PACCPQQCB91525
CPQCPդȤȹ⤵4CPQ34/26
ͳѷУ£ѡ649/1598/5
115ڡ 6:06:57 35305
ޤ륱ʳ
УäĹѤѣȤ򤪤ȡѣȡᣴ
ѷУãѤϣߣࣲ᣶
ѷУãѤФѷУáѣã¤Ϥ줾죳ȣ
äƴDz򤭤ޤ
115ڡ 10:05:36 35306
uchinyan
Ϥˤϡơϡ
ϡȤƤϴñȻפޤͤޤäȻפޤ
ХꥨϤޤŪŪʡȻפˡ񤤤Ƥޤ

AP P ˡBQ Q ˡ줾Ĺơθ R Ȥޤ
PAC = QCB RA//QCPCA = QBC PC//RB ʤΤǡRPCQ ʿԻշǤ
ȡM г PQ ʤΤǡʿԻշꡤRMC Ʊľˤޤ
ǡRP = QC = QB = 5 cmPC = PA = 3 cmPCR = 90ꡤPCR 345 ľѻѷǡRC = 4 cm Ǥ
ǡCPQ = PCR = PC * RC * 1/2 = 3 * 4 * 1/2 = 6 cm^2 Ǥ
ǡRA//QCPC//RB PACQCBRAB ջѷǡRA = RP + PA = 5 + 3 = 8 cm ꡤ
PACQCBRAB = 92564PACQCBRPCQ = 925(64 - 9 - 25) = 92530PACQCBCPQ = 92515
PABQCPQ = (9 + 15 + 25)15 = 4915
ǤǡCPQ = 6 cm^2 äΤǡ
PABQ6 = 4915PABQ = 6 * 49/15 = 98/5 cm^2
ˤʤޤ
ͥνȡ 115ڡ 11:16:50 MAIL:uchi@sco.bekkoame.ne.jp 35307
uchinyan
ǼĤɤߤޤ
ϡϤꡤ㴳ΥХꥨϤޤɤϡ
AP P ˡBQ Q ˡ줾Ĺ R ȤȤˡ
RPCQ ʿԻշPCR ڤ QRC 345 ľѻѷ
ȤȤȤˡΤ褦Ǥ͡
ʥХꥨȤƤϡ
ʿԻշϺ餺ˤȾʬǹͤ롤
PA//QCPC//QB 顤APC = PCQ = CQB ꡤľܤˡPACQCBCPQ = 92515 򤤤
ʤɤΤ褦Ǥ
ͥνȡ 115ڡ 11:29:27 MAIL:uchi@sco.bekkoame.ne.jp 35308
ߡ
⤦ȤˣޤǤ˵Τ̵ġ
ꡤĹ᤮ƷӤǤϤĤ֤Ǥ
115ڡ 15:33:27 35309
ݤä
ѷPCMM濴˲žPQŤʤ褦ˤ345λѷǤޤ
115ڡ 17:43:44 35310
ϥ饮㡼ƥ
դϡ٤ʤޤ

ȤäƤη׻Ǥߤޤ
115ڡ 20:50:51 HomePage:湩ؤ˥35311
7
äꡦ
117ڡ 15:20:22 35312

ǰ¿äˡDz⤷ޤ

ΥݥȤϡ֣ľѻѷ򸫤ĤפȤȤǤ

ФαĹ£ѤαĹҤȤȡ
ѷңУáѷңѣäϸˣľѻѷǤ
ѣУãѤϣ٤ʤΤǡ
ѷңУáỰѷңѣáУáߣͣáࣲᣳߡʣࣲˡࣲᣳ
äƻѷУãѡᣳߣ᣶

ѷУäܤ
ФդȤȹ⤵ϣࣵᣱ/
äƣߣ/ᣳȣ/

ѷãѣ¤ܤ
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äƣߣࣲᣱ

ܭܭ
ܣȣ/ܣ᣶ܣܣܣ/ᣱܣ/ᣱ

ꥸʥǤ꤬ΤϤФ餷ȤȻפޤ
ȤǤ
119ʷ 2:54:13 HomePage:35313
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P,M,QAB˿򲼤­ơH1,H2,H3Ȥ롣
PMH2˲­DȤ롣
PH1=3a,H1C=3bȤ롣
MH2=4a,CH2=bȤʤ롣
PH1H2Mܡ
PC^2=PH1^2+H1C^2
PM^2=PC^2+CM^2=PD^2+MD^2
6*a^2=24*b^2
a^2=4*b^2
ޤPH1^2+H1C^2=PC^2=9
9*a^2+9*b^2=9
a^2+b^2=1

a=1/5,b=2/5
ޤѤ
ͳѷABQP=APH1+QBH3+PH1H3Q=49ab
ä49*(1/5)*(2/5)=98/5

ɤƤ򤱤ʤΤǻʿȤޤġ
äѤꡢβ줤Ǥ͡
119ʷ 13:20:34 35314
fumio
Ϥ褦ޤ
1110ʲС 6:50:53 35315